The basis of today's electronic devices is a voltage regulator as all of the intelligent electronic devices run on DC voltage and the marketing is done on AC power. A basic understanding of the DC voltage regulator is therefore considered essential. There are mainly two types of power supply designs linear and switched power supplies. This document mainly discusses the linear type.
The most simplest approach to a hobbyist voltage regulator is to use 78XX series voltage regulator IC's to build one. Lets get into the task of building a simple 5V regulator using 7805. It is always intelligent to look into the datasheet of the IC before using one. Assuming we use LM7805 from Fairchild Semiconductor the IC would typically look like this. The part where 7805 is written would be the black material enclosing the original circuitry and the upper one which has a small 4 mm hole is made of metal to dissapate heat and is usally also the output pin anong with the output pin below the original IC.
Lets get into business of building a voltage regulator. If we skim through the document (http://www.fairchildsemi.com/ds/LM/LM7805.pdf ) we find that in the last pages of the document under Typical Applications
This is how the IC must be used be typically used according to the manufacturers. Now let us get into building one. We shall build a custom one that looks like
- 12V-0V-12V, 1A Step Down transformer
- Capacitor 470uf, 60v electrolytic
- 4 diodes, IN4007 would do
- Bread board to build the circuit
- RMC connectors to take the output
- Connecting plug to connect to AC mains (CEE 7/17) and some insulated multi strand wire (why?) to connect transformers to the plug
Connect the two input wires of the transformer to the multistrand wire and the other end of the multistrand wire to the plug. At this stage one may wish to put their multimeter to AC voltage mode and read the output from the secondary end by connecting the plug to the AC mains, It is not suggested that you do this concerning the safety due to existence of the AC main from the wire. Next build the rectifier bridge (Give attention to the diode directions). I strongly suggest that you use a bread board to build the circuit on (Building it on a pin board or an etched copper board is more of a permanent installation, Trust me you don't want to end up with this circuit for a regular electronic hobby kit). Connect the output from the transformer to the bridge Now i strongly suggest you to check the output voltage using a multimeter in DC voltage mode. Depending on various factors viz. Input voltage of the AC voltage, the practical drop out of the diodes you may get the voltage >20V and <8V. Anything out of this range, you may want to check the circuit you have built. Next connect the electrolytic capacitor. If you check the DC voltage now it must be almost same as before (why?). Next connect the IC to the circuitry and measure the output voltage. It must show 5.07V - 5.04V. Congratulations for having built your first Voltage Regulator.
Tweak 1 (Adjustable voltage regulator )
Though the above is an awesome regulator it is not the one you would want. What you would really want is the one that can be adjusted. And also the above one is a 5V power supply. Sometimes ( when working with Op-Amp's like uA741) we need +12V | 0V | -12V power supply. So an ideal power supply must be a controlled one. How to get a regulated power supply now. The answer lies in another magical IC by the name LM317. This IC provides trickery to just do the same. The datasheet of this IC says that this trickery is achived by two resistors connected as shown
The output is voltage is given by the above formula. You can neglect IadjR2 part as Iadj is a very small quantity usually around 50 uA. So the output of the IC would be V0 = 1.25V(1+R2/R1). In order to simplify the understanding of the IC we must remember the fact that the IC always produces a voltage of 1.25V between the pins adj and output
The first problem of a adjusting the voltage is thus almost solved now (almost ??) what must be the values of the resistors R1 and R2 ?, From the data sheet we find that typical value of Iadj must be 50 uA. So considering that the current flowing in R1 and R2 must be greater than this so as to affect the assumption made about neglecting IadjR2 part of the formula. Let the effective current through the resistor be atleast 20 times greater than Iadj. That gives us a current of 1mA so the resistor R1 would be 1.25V/1 mA, that is 1.25K resistor. We shall assume a standard value of 1K resistor. And so as to adjust the voltage fully until the highest value we can take a 10K pot for the R2. This under all favourable conditions must give us an max output voltage 1.25(1+10/1) = 13.75V. This isn't possible in the present circuitry as the input voltage from the regulator may not be that high but it is fairly possible to reach voltages of 12V - 10V DC for max voltage and the min voltage would be 1.25V DC (Oops..).
Now to tackle the second problem, the dual mode ( both positive and negative Voltages ). This is fairly simple. Simply build two of these adjustable regulators (that means another bridge from the remaining 12V wire and 0V wire and then the regulator circuit ) and connect one of their ground to anothers output voltage. Now the output voltage of the circuit taking the point at ground and output voltage short as the refrence voltage would be +ve at the first output and - ve voltage can be taken from the ground of the second regulator.
Tweak 2 ( Current Booster )
The datasheet document claims to output a max of 1A of current which in real sense would be more than sufficient for most of the regular applications but we missed a point. Lets say we are using a transformer to step down the AC voltage from the mains (220V-230V, 50-60Hz) to 12V-0V-12V,50-60Hz AC and then rectify it using a conventional rectifier the output voltage must then be around 9V DC (say) the output of a 7805 is then 5V therefore the voltage drop on the regulator IC is around 4V. Then the power dissapated on the rectifier must be 4Vx1A = 4W. Seeing the document we see that the the thermal resistence from junction to the air is 65 0C/W therefore the temperature diffrence between junction and the outside must be 65 x 4 = 260 0C. The datasheet lists that the maximum current is 2.2A when the junction temperature is maintained at 25 0C. Considering we do the same at 1A ( must be easier at 1A ). So let us say the Junction temperature is at 25 0C. Then the temperature of the outside body of the IC must be 25 0C - 260 0C = -235 0C. That means the outside of our IC must be maintained at -235 0C or at ~38K something only achievable using Liquid Helium (Well Fairchild where did you mention that?!!!). In short the output current can only be a maximum of 100 mA from these conventional IC's without use of a heat sink. Anything greater would heat up the IC rapidly and burn it out. That puts a serious limitation on the current handling capacity of the IC. Though in most of the cases this must be more than sufficient (Typical useage for a hobbyist would be a max of 50 mA) you will understand in the next section why this restriction is a backlog for a lot of awesomeness.
Now getting to the problem. How to boost the current in the output pin?. The answer lies in datasheet itself by using an extra transistor this problem can be overcome
Neglect the capacitors around they aren't required when you have a filter of 470uF after the rectifier R1 must be very small. The document suggests 3ohms, I suggest you find the smallest value you can find. The document also says the transistor to be BD536, a power transistor that can handle very high output currents. Using this will allow you to handle currents up to ~1A. Datasheet claims up to 8A, But we know how realistic the claim would be
I don't really suggest you to use this transistor itself, try others, read their datasheets and experiment. 2N2955 would allow you to get currents upto 1A~2A (According to the datasheet the maximum would be 7A) though that much current you will never use as a hobbyist, It would be a cool thing to have. For small applications BC548 would do, but I would not suggest it. It would be an understatement to use one. There are lots of other transistors available. The resistor is used to provide the required voltage between collector and the base. Read the document and decide upon the resistor to be used based on the power that is being used. Its usually enough to use smaller resistors of around 22 ohms. The high current Power transistor 2N2955 would typically look like
Tweak 3 (USB Charger for Mobile phones)
If you have been through the USB documentation (why would anyone do that??). You will find that the USB host must provide a constant voltage of 5V. Most of the mobiles exploit this into charging their battery. This reduces the number of physical ports they must provide on the phone. The same port can be used as a USB slave and also for charging purposes. Now out 5V regulator can be used as a mobile phone charger ( Current Boost is must, Trust me it doesn't work otherwise. The current drawn from the mobile phone is great that the voltage soon drops below acceptable values from the IC ). If you have designed a 5V regulator or adjustable regulator adjusted to 5V with current boost then connect a USB female pin. Depending on the type of the female pin that you may find in the market the pin out would look like this.
Type A is the most common one used in the market and also mobile USB cables are of male type A connector on one end, So I would suggest you get type A female pin for all good purposes. If you are using a adjustable voltage regulator make sure you set it to 5V so as to avoid any damage to the mobile phone.
Tweak 4 (Overload Protection )
Now that we have all the designs for a stable voltage regulator, lets look at improving some of the operation parameters. Shortcircuit overload protection is the easiest way to avoid high power drain due to short circuit that can damage the circuitry and lead you into lot of problems. Refering back to the datasheet we get the easiest way to implement one would be
The transistor suggested is TIP42. You may use BD536 also with no much change in the design. Feel free, experiment. VBEQ2 is the voltage drop between base and collector of Q2. ISC is the short circuit current. This will be the maximum current that can be drawn from the regulator. By this we limit the current that can be drawn from the IC, thus protecting it against damage.
- Read about Current fold back technique that further reduces power drain in the times of short circuit
- Read about Switching regulators
- Check out Buck and Boost voltage converters